Currently shortintertext is left aligned, how to make it right aligned? using \raggedright doesnt work
MWE
\documentclass{article}\usepackage{amsmath, mathtools}\usepackage{derivative} % Derivative\makeatletter\newcommand*\yesnumber{\incr@eqnum\tag{\theequation}}\makeatother\begin{document}\begin{flalign*}\label{eq:1.1-y}& y = \frac{c_0}{\varphi(x)}+ \frac{1 }{\varphi(x)} \,\int{\left(\frac{1}{4}\,x^3\right)\,\varphi(x)\,\odif{x}} % % % = & \\[3ex] \shortintertext{\raggedright Using \eqref{eq:1.1-phi_x}} & % & \text{Using \eqref{eq:1.1-phi_x}} \\& = \frac{c_0}{\left(c_1\,e^{x^2/8}\right)}+ \frac{1 }{\left(c_1\,e^{x^2/8}\right)} \,\int{\left(\frac{1}{4}\,x^3\right)\,\left(c_1\,e^{x^2/8}\right)\,\odif{x}} = &\\& = \frac{c_0}{\left(c_1\,e^{x^2/8}\right)}+ \frac{1 }{e^{x^2/8}} \,\int{\left(\frac{1}{4}\,x^3\right)\,\left(e^{x^2/8}\right)\,\odif{x}} = &\\& & \\ \shortintertext{\raggedright Using \eqref{eq:1.1-prim}} & = c_2\,e^{-x^2/8}+ \frac{1}{e^{x^2/8}} \,\left( \left(x^2-8\right)\,e^{x^2/8} \right) = &\\& \yesnumber = c_2\,e^{-x^2/8}+ x^2-8 = &\\& & \\ \shortintertext{\raggedright Using \eqref{eq:1.1-c_2}} & = 4\,e^{-x^2/8} + x^2 - 8 % % % &\\[3ex]& c_2 = c_0/c_1& \end{flalign*}% solving y(0) = -4\begin{flalign*}\label{eq:1.1-c_2}&& \\ \shortintertext{\raggedright Using \eqref{eq:1.1-y}} & \yesnumber y(0) = c_2\,e^{-0^2/8}+ 0^2 - 8 = c_2 - 8 = - 4 \implies c_2 = 4&\end{flalign*}% φ(x)\begin{flalign} \label{eq:1.1-phi_x}& \varphi(x) = \exp{\left( \int{\frac{1}{4}\,x\,\odif{x}} \right)} = \exp{\left( \frac{1}{4} \left( \frac{x^2}{2} + c \right) \right)} = \exp{\left( \frac{c}{4} \right)} \,\exp{\left( \frac{x^2}{8} \right)} % \notag % = &\\& = c_1\,e^{ \frac{x^2}{8} } ; &\\& \notag c_1 = e^{c/4}& \end{flalign}% prim\begin{flalign*}\label{eq:1.1-prim}& P\left( \left(\frac{1}{4}\,x^3\right)\,\left(e^{x^2/8}\right) \right) = P\left( \left( x^2 \right) \,\left( e^{x^2/8} \,\frac{x}{4} \right) \right) = P\left( \left( x^2 \right) % u \,\left( e^{x^2/8} \right)' % v' \right) = &\\& = % u\,v x^2\,P\left( \left( e^{x^2/8} \right)' \right) % P(v\,u') - P\left( P\left( \odv{}{x}\left( e^{x^2/8} \right) \right) \,\odv{x^2}{x} \right) = &\\& = x^2\,e^{x^2/8} - P\left( e^{x^2/8} \,2\,x \right) = x^2\,e^{x^2/8} - 8 \,P\left( e^{x^2/8} \,x/4 \right) = &\\& = \left(x^2-8\right) \,e^{x^2/8} \yesnumber& \end{flalign*}\end{document}